ap calculus

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f(x)=x^3-2x^2+x and f'(x)=3x^2-4x+1
Find the value(s) of x where f(x) has a horizontal tangent (slope=0)

• ap calculus -

horizontal slope means f' = 0
f'(x) = (3x-1)(x+1)

now it should be clear.

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