Algebra 2

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How do i get the perfect square of:
3x^2+7x=-9

  • Algebra 2 -

    Did you mean "solve by completing the square " ?

    if so, then first divide by 3

    x^2 + (7/3)x = -3
    x^2 + (7/3)x + 49/36 = -3 + 49/36
    (x+7/6)^2 = -59/36
    x+7/6 = ± √59 i /6
    x = (-7 ± i√59)/6

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