How do i get the perfect square of:
3x^2+7x=-9
Did you mean "solve by completing the square " ?
if so, then first divide by 3
x^2 + (7/3)x = -3
x^2 + (7/3)x + 49/36 = -3 + 49/36
(x+7/6)^2 = -59/36
x+7/6 = ± √59 i /6
x = (-7 ± i√59)/6
3x^2+7x=-9
if so, then first divide by 3
x^2 + (7/3)x = -3
x^2 + (7/3)x + 49/36 = -3 + 49/36
(x+7/6)^2 = -59/36
x+7/6 = ± √59 i /6
x = (-7 ± i√59)/6