Calculate Triangle G°, free energy change, that occurs when 12g of Shila react with excess And at 298k according to the following reaction: N2(g)+3H2(g)<======>2NH3(g) Triangle G°=-34KJ/mole
To calculate the free energy change (∆G°) for the given reaction, you need to use the formula:
∆G° = ∆G°f(products) - ∆G°f(reactants)
First, you need to determine the moles of substances involved in the reaction. In this case, you are given the mass of Shila and the reaction stoichiometry.
The molar mass of Shila (N2) is 28 g/mol. Therefore, 12 grams of Shila is equal to:
12 g / 28 g/mol = 0.4286 mol
According to the balanced equation, for 1 mole of N2, you produce 2 moles of NH3. Hence, the number of moles of NH3 produced is:
0.4286 mol N2 × (2 mol NH3 / 1 mol N2) = 0.857 mol NH3
Now that you have determined the moles of reactants and products, you can calculate the ∆G° for the reaction:
∆G° = ∆G°f(NH3) - ∆G°f(N2) - 3 × ∆G°f(H2)
The value given for ∆G° is -34 kJ/mol, which is the standard free energy change for the reaction.
Rearranging the equation, you get:
∆G°f(NH3) = ∆G°f(N2) + 3 × ∆G°f(H2) - ∆G°
To calculate ∆G°f for each species, you would look up the values in a standard thermodynamic table or use a database. Let's assume the values are:
∆G°f(NH3) = -45 kJ/mol
∆G°f(N2) = 0 kJ/mol
∆G°f(H2) = 0 kJ/mol
Substituting the values into the equation:
∆G°f(NH3) = 0 kJ/mol + 3 × 0 kJ/mol - (-34 kJ/mol)
∆G°f(NH3) = 0 kJ/mol + 0 kJ/mol + 34 kJ/mol
∆G°f(NH3) = 34 kJ/mol
Therefore, the free energy change (∆G°) for the reaction is 34 kJ/mol.