the cost of 6 cows are same as cost of 8 goats. if cost of 9 cows and twice numbered goats is rs. 9000, then find the cost of 3 cows and 6 goats?

(Here , twice numbered goats means 9 * 2 = 18)

Let cost of cow be x and goat be y

6x=8y(given)
9x+18y=9000
x+2y=1000
X=1000-2y
Equating value of x in next step we get
6000-12y=8y
6000=20y
So y = 300 than x = 400
So cost of 3x+6y= 1200+1800
3000 RS is the cost of 3 cows and 6 goats
VERIFICATION
9X+18Y= 9000
3600+5400= 9000

9cows + 18goats = 9000

Divide the whole equation with 3
3cows + 6goats = 3000

As it is given that 9x+3y=9000

So if we divide the whole equation by 3 on both sides we get that:
3x+6y=₹3000

Thanks for seeing my answer

Heya

Well, let's do some math and have some fun along the way!

If the cost of 6 cows is the same as the cost of 8 goats, we can say that 6 cows = 8 goats.

Now, we are given that the cost of 9 cows and twice numbered goats (18 goats) is Rs. 9000.

So, let's set up an equation:

9 * cost of 1 cow + 18 * cost of 1 goat = Rs. 9000

Now, we need to find the cost of 3 cows and 6 goats.

Let's assign variables to the cost of 1 cow and the cost of 1 goat. Let's say the cost of 1 cow = C and the cost of 1 goat = G.

Now, we can rewrite the equation as:

9C + 18G = 9000

To find the cost of 3 cows and 6 goats, we substitute the values into our equation:

3C + 6G = ?

To solve the system of equations, we can multiply the entire equation by 3 to simplify it:

3(9C + 18G) = 3(9000)
27C + 54G = 27000

Now, we can divide the equation by 9 to get the value of C:

27C + 54G = 27000
C + 2G = 1000

Now, we can substitute the value of C into the equation we want to find:

3C + 6G = 3(1000) + 6G
3C + 6G = 3000 + 6G
3C = 3000

So, the cost of 3 cows and 6 goats is Rs. 3000.

I hope that brings a smile to your face!

To solve this problem, we can set up a system of equations. Let's assign variables to the unknown values:

Let's say the cost of one cow is C and the cost of one goat is G.

According to the problem, the cost of 6 cows is the same as the cost of 8 goats, so we can write our first equation:

6C = 8G -- (Equation 1)

Next, we are given that the cost of 9 cows and twice the numbered goats is Rs. 9000, so we can set up our second equation:

9C + 18G = 9000 -- (Equation 2)

Now we have a system of two equations with two unknowns. We can solve this system of equations to find the values of C and G.

To eliminate one of the variables, we can multiply Equation 1 by 9 and Equation 2 by 6:

54C = 72G -- (Equation 3)
54C + 108G = 54000 -- (Equation 4)

Now we can subtract Equation 3 from Equation 4 to eliminate the C variable:

54C + 108G - 54C = 54000 - 72G
108G = 54000 - 72G
180G = 54000
G = 54000 / 180
G = 300

Now that we have the value of G, we can substitute it back into Equation 1 to find the value of C:

6C = 8 * 300
6C = 2400
C = 2400 / 6
C = 400

So, the cost of one cow is Rs. 400 and the cost of one goat is Rs. 300.

To find the cost of 3 cows and 6 goats, we can simply multiply the cost of each animal by the number of animals:

Cost of 3 cows = 3 * Rs. 400 = Rs. 1200
Cost of 6 goats = 6 * Rs. 300 = Rs. 1800

Therefore, the cost of 3 cows and 6 goats is Rs. 1200 + Rs. 1800 = Rs. 3000.