if you draw two cards from a deck of 52 cards without replacing the first card, what is the probability that you will draw a spade and another spade?
13/52 * 12/51
Compare this question to the one you had here
http://www.jiskha.com/display.cgi?id=1355886109
To me they are the same thing, follow the same logic
To calculate the probability of drawing a spade and then drawing another spade without replacement, we need to break down the problem into two steps.
Step 1: Drawing the first spade
There are 13 spades in a deck of 52 cards. So, the probability of drawing a spade on the first draw is 13/52 or 1/4.
Step 2: Drawing a second spade
After the first spade is drawn, there are now 51 cards left in the deck, with 12 remaining spades. So, the probability of drawing another spade on the second draw without replacement is 12/51.
To find the overall probability of both events happening (drawing a spade and then another spade), you need to multiply the probabilities together:
Probability = (1/4) * (12/51) = 12/204 = 3/51 = 1/17
Therefore, the probability of drawing a spade and then drawing another spade without replacement is 1/17.