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how many legs altogether for 3 cows, 6 chickens,3 fish and 4 fish
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(3 * 4) + (6 * 2) = ?
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A farm has chickens and cows. All the cows have 4 legs, and all the chickens have 2 legs. Altogether, there are 82 cow and
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Cows | Chickens | Total Legs ------------------------------ 10 | 36 | 82 9 | 38 | 82 8 | 40 | 82 7 |
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impatient much? stop repeating your posts.
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At a farm, there are some cows and some chickens. The number of chickens is 3 times the number of cows.
If the animals have a
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Cows have 4 legs, chickens have 2 legs, so
cows ---x , chickens ---- y 4x + 2y = 148 2x + y = 74 y = 74 - 2x Could you tell me
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well, it has to be 4 x + 2 y = some number of legs :) if it is 148 then 4 x + 2 y = 148 divide that
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How to solve: There are 40 chickens and cows in the farmyard. There are 100 legs in all. How many are cows and how many are
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chickens = 40/2 cows = 100/4
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