math
posted by amaka .
if two square have the respective areas indicated in square yards,one with 25yards and the other 5 yards how many yards of fencing are needed to enclose the two regions

For the square with area 25 yd^2,
x^2 = 25; x = 5; where x is the length of a side of the square. The perimeter of this square is 5*4 = 20
For the square with area 5 yd^2,
y^2 = 5; y = 5^0.5; where y is the length of the side of this square. The perimeter of this square is 4*(5^0.5)
The total yards of fencing needed to enclose both is the sum of the perimeters of both squares, or 20 + 4*(5^0.5)