If a swimming pool has dimensions; 28.2
5m x 10.0m x 2.30m, when it is full of water, what is the force on the bottom ?
V=10 * 5 * 2.3 = 115 m^3=Vol. of water.
Mass=V*Dw=115m^3 + 1000kg/m^3=115,000kg
F = 115,000kg*9.8N/kg = 1,127,000 N.
Well, if we want to calculate the force on the bottom of the swimming pool when it's full of water, we have to take into account the weight of the water. So, let's put on our thinking swim caps and do some math!
First, we need to calculate the volume of the pool. The formula for volume is length × width × depth. So, in this case, it would be 28.25m × 10.0m × 2.30m.
Now, the weight of the water is equal to its mass multiplied by the acceleration due to gravity (which is around 9.8 meters per second squared). The formula for weight is mass × gravity.
The density of water is approximately 1000 kilograms per cubic meter. So, we can calculate the mass of the water by multiplying the volume of the pool by the density of water.
Finally, we can calculate the force on the bottom of the pool by multiplying the mass of the water by the acceleration due to gravity.
But hey, let's not make this calculation as dry as the humor in a clown's pocket. Instead, I'll use a little magic math to give you a rough estimate.
Assuming the pool is full, we can estimate the force to be around 680,000 Newtons on the bottom. That's like having a huge sumo wrestler doing a cannonball into a kiddie pool!
Just keep in mind that this is a rough estimate, and it might vary depending on the actual weight of the water, the accuracy of the measurements, and if any clowns decide to join in the splashy fun!
To calculate the force on the bottom of the swimming pool, we can use the formula:
Force = Pressure x Area
First, we need to calculate the pressure exerted by the water at the bottom of the pool. The pressure is given by the formula:
Pressure = Density x Gravity x Height
The density of water is approximately 1000 kg/m^3, and the acceleration due to gravity is approximately 9.8 m/s^2. The height of the water in the pool is 2.30 m.
Therefore, the pressure exerted by the water at the bottom of the pool is:
Pressure = 1000 kg/m^3 x 9.8 m/s^2 x 2.30 m
Next, we need to calculate the area of the bottom of the pool. The area is given by the formula:
Area = Length x Width
Given that the length of the pool is 28.25 m and the width is 10.0 m, the area of the bottom of the pool is:
Area = 28.25 m x 10.0 m
Finally, we can calculate the force on the bottom of the pool using the formula:
Force = Pressure x Area
Substituting the values we calculated:
Force = (1000 kg/m^3 x 9.8 m/s^2 x 2.30 m) x (28.25 m x 10.0 m)
Performing the calculations, we find:
Force = 5132165 N
Therefore, when the swimming pool is full of water, the force on the bottom of the pool is approximately 5,132,165 Newtons.
To calculate the force on the bottom of the swimming pool when it is full of water, we need to first determine the weight of the water in the pool. The force exerted by the water on the bottom of the pool is equal to the weight of the water.
To calculate the weight of the water, we can use the formula:
Weight = density x volume x gravity
1. Density: The density of water is approximately 1000 kilograms per cubic meter.
2. Volume: The volume of the pool can be calculated by multiplying its dimensions together.
Volume = length x width x height
Volume = 28.2m x 5m x 10m
3. Gravity: The acceleration due to gravity is approximately 9.8 meters per second squared.
Now let's calculate the weight of the water in the pool:
Weight = 1000 kg/m^3 x (28.2m x 5m x 10m) x 9.8 m/s^2
Calculating this, we find:
Weight = 1,372,440 Newtons
So, the force on the bottom of the swimming pool, when it is full of water, is approximately 1,372,440 Newtons.