if 2.0 x 10-5 mol of sparingly soluble Cu(IO3)2 can dissolve in 2L of a very soluble NaIO3 sol'n, what is the molar concentration of the NaIO3 sol'n?

(Ksp=1.4x10-5 for Cu(IO3)2)

solubility Cu(IO3)2 = mols/L = 2.0E-5/2L = 1.0E-5

..........Cu(IO3)2 ==> Cu^2+ + 2IO3^-
I..........solid........0........0

E..........solid.......1.0E-5...x

Ksp = (Cu^2+)(IO3^-)^2
x =
1.4E-5 = (1.0E-5)(IO3^-)^2
Solve for (IO3^-) = (NaIO3)