what mass of Iodine(I2) must be used to prepare a .960m solution if 1000g of ethanol (C2H5OH0 is used?

What mass iodine and what volume of ethanol are required to prepare 150 g of 5% solution. density of ethanol is 0.8 g/ml.

Why did the iodine go to school?

Because it wanted to get an "I" in chemistry!

In order to determine the mass of iodine needed to prepare the solution, we need some additional information. Could you please provide the desired volume of the solution or the concentration you'd like to achieve?

To determine the mass of iodine (I2) needed to prepare a 0.960m solution using 1000g of ethanol (C2H5OH), we need to follow these steps:

1. Determine the number of moles of ethanol (C2H5OH) using its molar mass.
2. Use the stoichiometry of the reaction between iodine (I2) and ethanol (C2H5OH) to find the molar ratio.
3. Calculate the number of moles of iodine (I2) needed.
4. Convert the moles of iodine (I2) to grams using its molar mass.

Step 1: Calculate the moles of ethanol (C2H5OH)
The molar mass of ethanol (C2H5OH) is calculated by adding the atomic masses of each element:

C = 12.011 g/mol * 2 = 24.022 g/mol
H = 1.008 g/mol * 6 = 6.048 g/mol
O = 15.999 g/mol + 1.008 g/mol = 16.007 g/mol

Total molar mass of ethanol (C2H5OH) = 24.022 g/mol + 6.048 g/mol + 16.007 g/mol = 46.077 g/mol

To find the number of moles, divide the mass of ethanol by the molar mass:

Number of moles of ethanol (C2H5OH) = 1000 g / 46.077 g/mol

Step 2: Determine the molar ratio
From the balanced chemical equation of the reaction between iodine (I2) and ethanol (C2H5OH), we know that the molar ratio is 1:1. This means that for every 1 mole of iodine, we need 1 mole of ethanol.

Step 3: Calculate the moles of iodine (I2)
The number of moles of iodine (I2) needed is the same as the number of moles of ethanol (C2H5OH) calculated in Step 1.

Number of moles of iodine (I2) = Number of moles of ethanol (C2H5OH)

Step 4: Convert moles of iodine (I2) to grams
Using the molar mass of iodine (I2) (126.90 g/mol), multiply the number of moles of iodine by its molar mass to get the mass in grams.

Mass of iodine (I2) = Number of moles of iodine (I2) * Molar mass of iodine (I2)

By following the above steps, you should be able to calculate the mass of iodine (I2) needed to prepare the 0.960m solution using 1000g of ethanol (C2H5OH).

m = mols/kg solvent

0.960m = mols/1 kg
mols = 0.960
mols I2 = grams I2/molar mass I2. That assume that the grams I2 calculated actually dissolves in 1 kg ethanol.