A plane cruising at 251 m/s accelerates at25 m/s2 for 9 s.What is its final velocity?Answer in units of m/s
The increase in speed is 25*9 = 225 m/s
Add that to the 251 m/s initial velocity.
The final velocity will be supersonic. This is hardly "cruising" unless it is a fighter jet or SST.
476
To find the final velocity of the plane, we can use the formula:
final velocity (v) = initial velocity (u) + (acceleration × time)
Given:
Initial velocity (u) = 251 m/s
Acceleration (a) = 25 m/s^2
Time (t) = 9 s
Using the formula, we can substitute the given values:
v = u + (a × t)
v = 251 m/s + (25 m/s^2 × 9 s)
Now we can calculate the final velocity:
v = 251 m/s + (225 m/s)
v = 476 m/s
Therefore, the final velocity of the plane is 476 m/s.