Pysics
posted by Anonymous .
A hot, just minted copper coin is placed in 112g of water to cool. The water temperature changes by 8.58 C and the temperature of the coin changes by 80.0 C. What is the mass of the coin? Disregard any energy trans to the waters surroundings and assume the specific heat of copper is 387 j/kg C. The heat of water is 4186 J/kg C. Answer in units of g.

Equate the heat loss of the coin and the heat gain of the water.
Heat transfer is M*C*(delta T)
Mcoin*387*80 = 0.112*4186*8.58
The only unknown is Mcoin.
Solve for it.
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