he solubility of the fictitious compound, administratium fluoride (AdF3) in water is 3.091×10−4 M. Calculate the value of the solubility product Ksp.
To calculate the value of the solubility product (Ksp) for administratium fluoride (AdF3), we can use the solubility information provided.
The solubility product (Ksp) expression for a compound is the mathematical representation of the equilibrium between the solid compound and its dissolved ions. For AdF3, the solubility product expression would be:
AdF3 (s) ⇌ Ad3+ (aq) + 3F- (aq)
The solubility of AdF3 is given as 3.091×10−4 M, which represents the concentration of the Ad3+ ions in the solution. Since AdF3 dissociates into 1 Ad3+ ion and 3 F- ions, the concentrations of the Ad3+ and F- ions in the solution will be 3.091×10−4 M and 3 × 3.091×10−4 M, respectively.
Therefore, the Ksp expression for AdF3 can be written as:
Ksp = [Ad3+] × [F-]^3
Substituting the concentrations, the expression becomes:
Ksp = (3.091×10−4) × (3 × 3.091×10−4)^3
Calculating this expression will give you the value of Ksp for administratium fluoride (AdF3) in water.