Calculus
posted by Mackenzie .
Evaluate the integral by changing to spherical coordinates.
The outer boundaries are from 0 to 1.
The middle one goes from sqrt(1x^2) to sqrt(1x^2)
The inner one goes from sqrt(1x^2z^) to sqrt(1x^2z^)
for 1/sqrt(x^2+y^2+z^2) dydzdx
I don't understand how to get the limits of integration. I know for rho it will be from 0 to 1. I want to know the process to get the boundaries for phi and theta since I have a few other similar problems to do.

Calculus 
Jennifer
The boundaries for phi are 0 to 2*PI
The boundaries for theta are 0 to PI
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