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standard form of the equation KClo3->KCl(5)+02(g) for a project
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2KClO3----->KCl2 +3O2
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2KClO3----->2KCl +3O2 I meant to have the equation like this
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How many milliliters of O2 will form at STP from 38.8 g KClO3?
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if 50.0 g of KCl reacts with 50.0 g of O2 to produce KClO3 according to the equation, how many grams of KClO3 will be formed?
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What volume of oxygen gas can be collected
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Related Questions
2KClO3 --> 2KCl + 3O2
What mass of O2 can be made from heating 125 g of KClO3? I know that the answer is 49 g O2 but I keep
Show that one mole of KCLO3 contains 122.55 grams.
2 KCLO3(s)->2 KCL(s) + 3 O2(g)
Oxygen gas can be generated by heating KClO3 in the presence of a catalyst.
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If 267 mL of O2, measured at STP, are obtained by the decomposition of the KClO3 in a 3.33 g mixture of KCl and KClO3, 2KClO3(s)
If 237 mL of O2, measured at STP, are obtained by the decomposition of the KClO3 in a 5.44 g mixture of KCl and KClO3,
2KClO3(s)-
Use this reaction to answer the question: 2KClO3 -> 2KCl + 3O2
If I start with 65g KClO3, how many mol O2 will be formed? How
Use this reaction to answer the question: 2KClO3 -> 2KCl + 3O2.
If I start with 65g KClO3, how many mol O2 will be formed? How
Oxygen gas can be generated by heating KClO3 in the presence of a catalyst.
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