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580/145 lowest term
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Divide the numerator by the denominator. What do you get?
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Can you guys help me?
-18/81 in lowest term? 5/12 in lowest term? 16/24 in lowst term? 25/55x .. simplify ?
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Which fraction is NOT equivalent to 16/24 a. 2/3 b. 5/8 c. 32/48 d.4/6 ^ sorry i meant this
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The sum of the first 10 term of an arithmetic sequence is 145 and the sum of the fourth and ninth term is five times the third
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10/2 (2a+9d) = 145 a+3d + a+8d = 5(a+2d) a=1 d=3
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The first term and last term of an arithmetic progression are -4 and 145 respectively. If the common difference is 4. (a) find
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I am Tolu
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The first term and last term of an arithmetic progression are -3 and 145 respectively .if the common difference is 4.(a) find
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You are told a=-3 and d = 4 so you can find any term using: term(n) = a + (n-1)d so term(12) = a +
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The sum of the first 10 terms of an arithmetic series is 145 and the sum of its fourth and ninth term is five times the third
Top answer:
just use what you know to find a and d: 10/2 (2a+9d) = 145 a+3d + a+8d = 5(a+2d)
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What are the values of a and b?
21 2 30 20 9 (1 point) A. a = 400/21 b - 580/21 B.a - 400/21 b - 20/21 C.a = 580/21 b = 29/21 D.a
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The values of a and b cannot be determined from the given options.
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i'm a bit stuck with this..
145/18 = x + x^2 what does x equal to? multiply each term by 18, then re-arrange to get 18x^2 + 18x -
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To solve the quadratic equation 18x^2 + 18x - 145 = 0, we can use the quadratic formula. The
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The first and last term of an AP are -3 and 145 , respectively .If the common difference is 4 Find the 12th ,25th and the number
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Tn = a + (n-1) d a = -3 d = 4 Tlast = -3 + (n-1)*4 = -3 + 4 n - 4 = -7 + 4 n = 145 so 4 n = 152 n =
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If the first and last term of an A.P are -3 and 145 respectively. If the common difference is 4, find the 12th term
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-3 + 11*4 = ___
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The first term of an ap are - 3 and 145, respectively if the common difference is 4 find the (a) 12th (b) 25 term
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so we have a = -3 d = 4 now just use your formula for the nth term. a_n = -3 + 4(n-1) = 4n-7 not
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