the net external force of the propeller of a 4.0 kg model airplane is 9.5 N forward.
What is the acceleration of the airplane?
Answer in units of m/s^2
Since F = m a ,
a = F/m = 9.5/4.0 = _____ m/s^2
(Forward)
To find the acceleration of the airplane, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
The net external force acting on the airplane is 9.5 N forward (assuming there are no other external forces). The mass of the airplane is 4.0 kg.
Using the formula for acceleration (a), net force (F), and mass (m):
a = F / m
Plugging in the values:
a = 9.5 N / 4.0 kg
a = 2.375 m/s^2
Therefore, the acceleration of the airplane is 2.375 m/s^2.
To find the acceleration of the airplane, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied on it and inversely proportional to its mass.
The formula for Newton's second law is:
F = ma
Where:
F represents the net force
m represents the mass of the object
a represents the acceleration
In this case, we are given that the net external force of the propeller is 9.5 N forward, and the mass of the airplane is 4.0 kg. We can substitute these values into the formula and solve for acceleration:
9.5 N = 4.0 kg * a
To find the acceleration, we can rearrange the equation to isolate 'a':
a = 9.5 N / 4.0 kg
Now, we can calculate the acceleration:
a = 2.375 m/s^2
Therefore, the acceleration of the airplane is 2.375 m/s^2.