10.0g of sodium chloride is dissoved in 300ml of 0.75mol/L magnesium chloride solution. Find the new concentration of chloride ions f the solution.

To find the new concentration of chloride ions in the solution, we need to consider the molar ratio between sodium chloride and chloride ions in the solution.

First, let's calculate the number of moles of sodium chloride dissolved in the solution. We can use the formula:

moles = mass of substance / molar mass

In this case, the mass of sodium chloride is given as 10.0g. The molar mass of sodium chloride (NaCl) is 22.99g/mol for sodium (Na) plus 35.45g/mol for chlorine (Cl). Therefore:

moles of sodium chloride = 10.0g / (22.99g/mol + 35.45g/mol) = 0.1738 mol

Next, let's calculate the total volume of the solution after dissolving the sodium chloride. We know that the initial volume of the magnesium chloride solution was 300mL.

So, the final volume of the solution is 300mL.

Now, let's find the concentration of chloride ions in the solution. Since magnesium chloride is a strong electrolyte, it dissociates completely into ions in solution. The molar ratio between magnesium chloride and chloride ions is 1:2.

Therefore, the moles of chloride ions in the solution are:

moles of chloride ions = 2 * moles of magnesium chloride

The initial concentration of the magnesium chloride solution is given as 0.75 mol/L (mol per liter). By multiplying the concentration by the volume of the solution, we can find the number of moles of magnesium chloride in the solution:

moles of magnesium chloride = 0.75 mol/L * 0.3 L = 0.225 mol

Finally, we can calculate the moles of chloride ions in the solution:

moles of chloride ions = 2 * 0.225 mol = 0.45 mol

To find the new concentration of chloride ions, we divide the moles of chloride ions by the new total volume of the solution:

new concentration of chloride ions = moles of chloride ions / total volume of solution

new concentration of chloride ions = 0.45 mol / 0.3 L = 1.5 mol/L

Therefore, the new concentration of chloride ions in the solution is 1.5 mol/L.

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