If an object with a density of 0.8 g/cc is placed in pure water is it correct that 80% of the object will be below the water line and 20% of the object will be above the water line?

Yes

well it depends i guess yes

To determine if 80% of the object will be below the water line and 20% will be above, we first need to understand how buoyancy works.

Buoyancy is the upward force exerted on an object submerged in a fluid, such as water. This force is equal to the weight of the fluid displaced by the object. If the buoyant force is greater than or equal to the weight of the object, the object will float. If the buoyant force is less than the weight of the object, the object will sink.

In this case, the density of the object is 0.8 g/cc, and it is being placed in pure water. The density of water is approximately 1 g/cc.

To determine the percentage of the object submerged, we need to compare the density of the object with the density of the fluid it is placed in. If the density of the object is less than the density of the fluid, it will float, and if it is greater, it will sink.

Comparing the density of the object (0.8 g/cc) with the density of water (1 g/cc), we can see that the object is less dense than water. Therefore, the object will float.

When an object floats, a portion of it is submerged, while the remaining portion remains above the water line. The submerged part of the object displaces an equal volume of water, causing the buoyant force to balance out the weight of the object.

The percentage of the object that is submerged (below the water line) can be calculated using the density ratio:

Submerged Percentage = (Density of Object / Density of Fluid) x 100

In this case, the submerged percentage would be:

Submerged Percentage = (0.8 g/cc / 1 g/cc) x 100 = 80%

Therefore, 80% of the object will be below the water line, and 20% will be above the water line when placed in pure water.