a hockey player accelerates a puck (m=.167 kg) from rest to a velocity of 50 m/s in 0.0121 sec. Determine the acceleration of the p7uck and the force applied by the hockey stick to the puck. Neglect resistance forces.
To determine the acceleration of the puck, we can use the formula:
acceleration (a) = change in velocity (Δv) / time (t)
Given that the initial velocity (u) is 0 m/s, the final velocity (v) is 50 m/s, and the time (t) is 0.0121 sec, we can calculate:
Δv = v - u
= 50 m/s - 0 m/s
= 50 m/s
a = Δv / t
= 50 m/s / 0.0121 sec
≈ 4132.23 m/s^2
Therefore, the acceleration of the puck is approximately 4132.23 m/s^2.
To determine the force applied by the hockey stick to the puck, we can use Newton's second law of motion:
Force (F) = mass (m) * acceleration (a)
Given that the mass (m) of the puck is 0.167 kg, and the acceleration (a) is approximately 4132.23 m/s^2, we can calculate:
F = m * a
= 0.167 kg * 4132.23 m/s^2
≈ 689.59 N
Therefore, the force applied by the hockey stick to the puck is approximately 689.59 Newtons.
To determine the acceleration of the puck, we can use the formula for acceleration:
Acceleration (a) = Change in velocity (Δv) / Time taken (Δt)
In this case, the change in velocity is given as 50 m/s (final velocity) and the time taken is 0.0121 s. Substitute these values into the formula:
a = 50 m/s / 0.0121 s
Calculating this, we get:
a ≈ 4132.23 m/s^2
So, the acceleration of the puck is approximately 4132.23 m/s^2.
To calculate the force applied by the hockey stick to the puck, we can use Newton's second law of motion:
Force (F) = mass (m) x acceleration (a)
The mass of the puck is given as 0.167 kg, and the acceleration we just calculated is 4132.23 m/s^2. Plug these values into the formula:
F = 0.167 kg * 4132.23 m/s^2
Mathematically, we have:
F ≈ 689.47 N
Therefore, the force applied by the hockey stick to the puck is approximately 689.47 Newtons.
a=(v-v₀)/t=v/t
F=ma