Lily and Sara each had an equal amount of money at first. After Lily spent $18 and Sara spent $25, Lily had twice as much as Sara. How much money did each of them have at first?
Here is your bar model:
This is a unit bar: [xxx]
Before - the had equal amounts, then they each spent some money. In the end, Lily has twice as much as Sara, or 2 units.
Lily [xxx][xxx]<----$18---->|
Sara [xxx]<-----$25-------->|
If they started out the same, the second unit bar for Lily must be equal to $25 - $18, so $7
[xxx]=$7
Lily had 2 units (2 x $7)+$18 at first.
Sara had 1 unit ($7)+$25 at first.
Thank you all family spend two hours to solve this problem with out x
To solve this problem, let's break it down step by step.
Let's start by assigning variables to the unknown quantities. Let's say that the amount of money they had at first is "x" dollars.
According to the problem, after Lily spent $18, she had twice as much money as Sara. So, after Lily spent $18, she had (x - 18) dollars, and Sara had (x - 25) dollars.
We can write the equation to represent this situation: (x - 18) = 2 * (x - 25)
Now, let's solve the equation and find the value of "x".
Distribute the 2 on the right side of the equation: x - 18 = 2x - 50
Combine like terms: x - 2x = -50 + 18
Simplify: -x = -32
Divide both sides of the equation by -1: x = 32
So, the initial amount of money both Lily and Sara had is $32.
Therefore, Lily and Sara each had $32 at first.
Let the amount each had initially be x.
x - 18 = 2*(x - 25) = 2x - 50
x = 32