posted by John Smith .
A 1.73 g sample of a molecular compound
is dissolved in 105 g of tetrachloromethane
(carbon tetrachloride). The normal boiling
point of the solution is 61.51C, the normal
boiling point of CCl4 is 61.2C. The boiling
point constant for CCl4 is 4.95 K · kg/mol.
What is the molar mass of the compound?
Answer in units of g/mol
AP Chem -
delta T = Kb*m
Solve for m
m = mols/kg solvent
Solve for mols
mols = grams/molar mass
Solve for molar mass.