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A long wire carries a current of 20 A along the directed axis of a long solenoid. The field due to the solenoid is 4 mT. Find the field at a point 3 mm from the solenoid axis.

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    Magnetic field due to the long wire
    B₁=μ₀I/2πb=4π•10⁻⁷•20/2•π•0.003=1.3•10⁻³ T
    ( B₁ is directed normal to the axis of solenoid)
    B=sqrt(B₁²+B₂²) =sqrt{(1.3•10⁻³)²+(4•10⁻³)²} =4.2•10⁻³ T

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