One question left for the night and i am stumped ... I need to find the sixth term of a geometric sequence in which a-sub-one = -7 and r = 3 .... Thanks in advance for you help!
To find the sixth term of a geometric sequence when you are given the first term (a-sub-one) and the common ratio (r), you can use the formula:
a-sub-n = a-sub-one * (r)^(n-1)
Given that a-sub-one = -7 and r = 3, we need to find a-sub-six. Plugging these values into the formula, we get:
a-sub-six = -7 * (3)^(6-1)
Now we need to calculate (3)^(6-1), which means raising 3 to the power of 5. This can be done using exponentiation:
(3)^5 = 3 * 3 * 3 * 3 * 3 = 243
Therefore, the sixth term of the geometric sequence is:
a-sub-six = -7 * 243
By multiplying -7 with 243, we can find the value of the sixth term:
a-sub-six = -1701
So, the sixth term of the given geometric sequence is -1701.