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Find parametric equations of the line that is tangent to the parabola y = x^2 at the point (−2, 4).

  • maths -

    dy/dx = 2x
    so at (-2,4) slope is -4

    y-4 = -4(x+2)
    y-4 = -4x - 8 = k

    -4x-8 = k
    -4x = k + 8

    x = -2 - k/4
    y = 4 + k

    Parametric equations for linear function ??
    Why not just
    y = -4x -4 ??

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