maths
posted by ramesh .
Find parametric equations of the line that is tangent to the parabola y = x^2 at the point (−2, 4).

dy/dx = 2x
so at (2,4) slope is 4
y4 = 4(x+2)
y4 = 4x  8 = k
4x8 = k
4x = k + 8
x = 2  k/4
y = 4 + k
Parametric equations for linear function ??
Why not just
y = 4x 4 ??