physics

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An object is placed 3cm in front of a diverging lens of focal length of 6cm. the heihgt of the object is 1.5 cm. calculate the image distance and height of the image

  • physics -

    -1/6-1/3=-1/2
    image distance=-2

    hi/ho=-di/do
    hi/1.5=-(-2)/3
    hi=(2/3)x(3/2)
    hi=1

  • physics -

    i wantere being if two different conventions are there in applications. Since I saw two different systems being followed.

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