physics
posted by hunaa physics .
An object is placed 3cm in front of a diverging lens of focal length of 6cm. the heihgt of the object is 1.5 cm. calculate the image distance and height of the image

1/61/3=1/2
image distance=2
hi/ho=di/do
hi/1.5=(2)/3
hi=(2/3)x(3/2)
hi=1 
i wantere being if two different conventions are there in applications. Since I saw two different systems being followed.
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