Calculus
posted by toma .
A bacteria culture contains 200 cells initially and grows at a rate proportional to its size. After half an hour the population has increased to 360 cells.
(a) Find the number of bacteria after t hours.
(b) Find the number of bacteria after 4 hours.
I found part a, P(t)= 200e^(1.2*t)
but when I solve part b it's different than the model answer!

I found the following:
360 = 200 e^(.5k) , where k is a constant
1.8 = e^(.5k)
ln 1.8 = .5k lne
.5k = ln 1.8
k = 1.1755733..
so Number = 200 e^(1.755733t)
when t=4
number = 200 e^4.702293..
= 22039.9
or appr 22040 bacteria
It looks like you rounded of the value of k too early.
Since you are using a calculator anyway, why round off any numbers at all ?
Just use them the way they appear on your device, so there is no need to reenter any numbers.
I also use the memory locations of my calculators to store any intermediate results.
If we use your value of k = 1.2
Number = 200 e^(4*1.2) = appr 24302 which is significantly different from the answer I got.