Graph each compound inequality.

f>3 or f< -2
Which one do I graph? Im confused.....

everything to the left of negative two and everything right of positive three

not including the exact points -2 and +3 so an open circle around those points, not a solid dot.

http://www.sparknotes.com/math/algebra1/inequalities/section4.rhtml

To graph the compound inequality f > 3 or f < -2, you need to graph both inequalities separately and then combine their solutions. Here's how to do it step by step:

1. Start by graphing f > 3:
- Draw a number line and label it with numbers to include the range of possible values for f.
- Since the inequality is f > 3, you need to represent all the values greater than 3 on the number line.
- You can do this by drawing an open circle above the number 3 and then extending a ray to the right to indicate all the values greater than 3.

2. Next, graph f < -2:
- Continue using the same number line.
- This time, the inequality is f < -2, so you need to represent all the values less than -2 on the number line.
- Draw an open circle below the number -2 and then extend a ray to the left to indicate all the values less than -2.

3. To combine the graphs:
- Look at the two graphs you drew for f > 3 and f < -2.
- Shade the region on the number line that is common to both graphs.
- In this case, since the compound inequality is f > 3 or f < -2, you need to shade the region that includes values greater than 3 or values less than -2. This means you will shade everything except the region between -2 and 3.

By following these steps, you will have graphed the compound inequality f > 3 or f < -2.