math precalc h
posted by sam .
It says which expressiion is equivalent to
sec T + csc T / 1+tan T
a. sin t b. cos t c. tan t d. csc t
I'm not sure what to do first to find it out.

math precalc h 
Reiny
(sec T + csc T) / (1+tan T)  notice the insertion of the necessary brackets
= (1/cosT + 1/sinT)/(1 + sinT/cosT)
= ( (sinT + cosT)/(sinTcosT) )/( (cosT+sinT)/cosT )
= cosT/(sinTcosT)
= 1/sinT
= cscT
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