A student dissolves 196 g of H3PO4 (Molar mass = 98 g) in enough water to make one liter of solution. The molarity of the solution is ?
To calculate the molarity of a solution, we need to use the formula:
Molarity (M) = number of moles / volume of solution (in liters).
First, let's calculate the number of moles of H3PO4:
Number of moles = mass of substance / molar mass
Mass of H3PO4 = 196 g
Molar mass of H3PO4 = 98 g/mol
Number of moles = 196 g / 98 g/mol = 2 moles
Now, we need to calculate the volume of the solution. We are given that we have made one liter of solution, so the volume is 1 liter.
Now we can plug the values into the formula:
Molarity = 2 moles / 1 liter = 2 M
Therefore, the molarity of the solution is 2 M (or 2 mol/L).
To find the molarity of a solution, we need to determine the number of moles of solute (H3PO4) and then divide it by the volume of the solution in liters.
First, let's calculate the number of moles of H3PO4 in 196 g. We can use the formula:
Number of moles = mass / molar mass
Where:
- mass is the given mass of the substance (196 g)
- molar mass is the molar mass of the substance (98 g/mol)
Number of moles = 196 g / 98 g/mol = 2 mol
Since we dissolved the substance in enough water to make one liter of solution, the volume of the solution is 1 liter.
Finally, we can calculate the molarity using the formula:
Molarity = number of moles / volume of solution
Molarity = 2 mol / 1 L = 2 M
Therefore, the molarity of the solution is 2 M (moles per liter).
a. .500m
b. 2.00m
c. 3.00m
d. 6.00m