chemistery

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the mass percent of a solution prepared by dissolving 0.500 moll KCL ( Molar mass = 74.6 g) in 850 g of water is ?

  • chemistery -

    mass KCl = mols x molar mass.
    % w/w KCl = [grams KCl/(g KCl + 850)]*100 = ?

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