How much energy, in joules, must be absorbed to convert to Na+ all the atoms present in 1.00mg of gaseous Na? The first ionization energy of Na is 495.8 kJ/mol
1 mg = 0.001g
mols Na = 0.001g/23 = ? mol.
E = 495.8 kJ/mol x ?mol
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To find the energy required to convert all the atoms present in 1.00 mg of gaseous Na to Na+ ions, we can use the following steps:
Step 1: Convert the mass of Na from milligrams to grams.
1.00 mg = 0.001 g
Step 2: Calculate the number of moles of Na using its molar mass.
The molar mass of Na is 22.99 g/mol.
Number of moles of Na = Mass (g) / Molar mass (g/mol)
Number of moles of Na = 0.001 g / 22.99 g/mol
Step 3: Calculate the energy required to ionize one mole of Na atoms.
The first ionization energy of Na is given as 495.8 kJ/mol.
Step 4: Calculate the energy required to ionize all the moles of Na atoms.
Energy required = Number of moles of Na * Ionization energy of Na
Let's plug in the values and calculate the energy:
Number of moles of Na = 0.001 g / 22.99 g/mol = 4.35 x 10^-5 mol
Energy required = 4.35 x 10^-5 mol * 495.8 kJ/mol
Now, we need to convert kilojoules to joules:
1 kJ = 1000 J
Energy required = (4.35 x 10^-5 mol * 495.8 kJ/mol) * 1000 J/kJ
Calculating the value:
Energy required = 21.43 J
Therefore, the energy required to convert all the atoms present in 1.00 mg of gaseous Na to Na+ ions is approximately 21.43 joules.