Mary and Peter had a total of Rs 480.After Peter spent Rs 20, he had 3 times as much as Mary.How much did Mary have?
Let the original amounts be M and P.
M + P = 480
P - 20 = 3 M
Subtract the second equation from the first.
M + 20 = 480 - 3 M
4 M = 460
M = 115 rupees
P = 365
First Peter will spend 20
SO,
480-20=460
THEN divided by 4 Since Peter has the three times of what marry has
So,
460÷4=115
Then 115×3=345
So Peter Has 345
And marry has 115
Which will be
345+115=460
Done.
mam studnts can not undrstnd the plus of m and p so if you can chng this qustn in easy way this wil b btr
I didn't understand your workings and what solution did you make it in. And when l divided 3 with 480 so l got the answer of 160. And when minus the following number 160 into 20 so l got the answer of 140.
To find out how much Mary had, let's break down the problem and find the solution step by step.
Let's assume Mary had Rs X initially.
After Peter spent Rs 20, he had 3 times as much as Mary, so Peter had 3X - 20.
The total amount they had together was Rs 480, so we can set up an equation:
Mary's amount + Peter's amount = Total amount
X + (3X - 20) = 480
Simplifying the equation, we get:
4X - 20 = 480
To solve for X, we'll add 20 to both sides of the equation:
4X = 480 + 20
4X = 500
Now, divide both sides by 4 to isolate X:
X = 500 / 4
X = 125
So, Mary initially had Rs 125.