Find the equation of the line that passes through the pair of points. Write your answer in slope-intercept form (2,-5)(2,-1)
m = slope = (Y2-Y1)/X2-X1)
m = (-1+5)/(2 - 2) Undefined so vertical line through (2, 0), no y axis intercept.
equation is x = 2
To find the equation of a line that passes through two given points, we can use the slope-intercept form of a linear equation, which is represented as y = mx + b.
First, we need to find the slope of the line. The slope (m) can be calculated using the formula:
m = (y2 - y1) / (x2 - x1)
Given the points (2, -5) and (2, -1), we can substitute the coordinates into the formula:
m = (-1 - (-5)) / (2 - 2)
m = 4 / 0
Since the denominator is zero, we can conclude that the slope is undefined, indicating that the line is vertical. A vertical line does not have a slope-intercept form equation because its slope is undefined. However, we can still write the equation using a different form, called the point-slope form, which is:
x = a
In our case, the equation of the line passing through the points (2, -5) and (2, -1) is:
x = 2
To find the equation of a line that passes through two points, we can use the formula:
y - y1 = m(x - x1)
where (x1, y1) represents one of the points on the line and m represents the slope of the line.
Given the two points (2, -5) and (2, -1), we can see that the x-coordinate is the same for both points, which means the line is vertical. The equation of a vertical line is of the form x = k, where k represents the x-coordinate.
In this case, since both points have an x-coordinate of 2, the equation of the line is x = 2.
Please let me know if there's anything else I can help with.