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chemistry

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what are the equilibrium concentrations of Pb2+ and F- in a saturated solution of lead (II)flouride if the Ksp for PbF2 is 3.2*10^-8?

  • chemistry -

    ..........PbF2 ==> Pb^2+ + 2F^-
    I.........solid.....0.......0
    C.........solid.....x.......2x
    E.........solid.....x.......2x

    Ksp = (Pb^2+)(F^-)^2
    Substitute the E line into Ksp expression and solve for x and 2x.

  • chemistry -

    .000000006

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