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The function f:x =2x+1/x-3 and g:x =1-x/2

a. For what value of x is 'f' undefined?
b. Find 'f' inverse and hence solve f(x) =1/3.

c.Show that fg(x) -gh(x).

  • math -

    f is undefined when x-3 is zero, because division by zero is undefined.

    f = (2x+1)/(x-3)
    (x-3)f = 2x+1
    fx-3f = 2x+1
    (f-2)x = 3f+1
    x = (3f+1)/(f-2)

    now plug in x(1/3) to get -6/5

    dunno what h is

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