math
posted by lindsay .
The function f:x =2x+1/x3 and g:x =1x/2
a. For what value of x is 'f' undefined?
b. Find 'f' inverse and hence solve f(x) =1/3.
c.Show that fg(x) gh(x).

f is undefined when x3 is zero, because division by zero is undefined.
f = (2x+1)/(x3)
(x3)f = 2x+1
fx3f = 2x+1
(f2)x = 3f+1
x = (3f+1)/(f2)
now plug in x(1/3) to get 6/5
dunno what h is