posted by lindsay

I need to sketch the graph of t(x)=2x^2 +3x > or equal to 10x-x^2. How do I work out the points to plot on the graph?

  1. Steve

    one way: graph both functions and see where one is above the other. Visit

    and you can graph up to three functions at once. Set the y range for -20 to 20.

    algebraic way:

    2x^2+3x > 10x-x^2
    3x^2 - 7x > 0
    x(3x-7) > 0
    either both factors are negative, or both are positive:
    x is in (-∞,0) U (7/3,∞)

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