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If 1600cals of heat are added to 50g of water initally at a temperature of 10c what is the final temperature of the water?

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    Q = m*C*(Tf-Ti)

    Q is heat
    m is mass of water
    C is the specific heat of water (look this up in cal/(g*C))
    Tf is final temperature
    Ti is initial temperature

    1600 = 50*1*(Tf-10)

    solve for Tf

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