If 1600cals of heat are added to 50g of water initally at a temperature of 10c what is the final temperature of the water?

Q = m*C*(Tf-Ti)

Q is heat
m is mass of water
C is the specific heat of water (look this up in cal/(g*C))
Tf is final temperature
Ti is initial temperature

1600 = 50*1*(Tf-10)

solve for Tf

To find the final temperature of the water, we can use the equation:

Q = mcΔT

Where:
Q = heat energy gained or lost by the water (in calories)
m = mass of the water (in grams)
c = specific heat capacity of water (in calories/gram°C)
ΔT = change in temperature (final temperature - initial temperature)

First, let's calculate the heat energy gained by the water:

Q = 1600 calories

The specific heat capacity of water is approximately 1 calorie/gram°C.

m = 50 grams
c = 1 calorie/gram°C

Now, let's rearrange the equation to solve for ΔT:

ΔT = Q / (mc)

ΔT = 1600 calories / (50 grams * 1 calorie/gram°C)

ΔT = 1600 / 50 °C

ΔT = 32 °C

To find the final temperature, we add the change in temperature to the initial temperature:

Final temperature = Initial temperature + ΔT
Final temperature = 10 °C + 32 °C
Final temperature = 42 °C

Therefore, the final temperature of the water is 42 °C.

To find the final temperature of the water, we can use the principle of heat transfer. The heat gained by the water can be calculated using the formula:

Q = m * c * ΔT

where:
Q is the heat gained (or lost)
m is the mass of the water
c is the specific heat capacity of water
ΔT is the change in temperature

In this case, we have the following information:
Q = 1600 calories
m = 50 grams
c = 1 calorie/gram °C (specific heat capacity of water)
The initial temperature (T1) is 10°C.

Now we can rearrange the formula to solve for ΔT:

ΔT = Q / (m * c)

Substituting the known values:

ΔT = 1600 cal / (50 g * 1 cal/g°C)
ΔT = 1600 / 50
ΔT = 32°C

To find the final temperature (T2), we add ΔT to the initial temperature (T1):

T2 = T1 + ΔT
T2 = 10°C + 32°C
T2 = 42°C

Therefore, the final temperature of the water would be 42°C after adding 1600 calories of heat to 50g of water initially at a temperature of 10°C.