how do I explain how to solve the following problem
2 X 10 square + 3 X 10 to the first + 5 X 10 to the zero +7 X 10 to the negative one
how to write 0.09 3/40.5 1/3 2/5
Please do not append a new question to end of somebody else's post
2 X 10 square + 3 X 10 to the first + 5 X 10 to the zero +7 X 10 to the negative one
in "math"
= 2(10^2) + 3(10) + 5(10^0) + 7(10^-1)
= 200 + 30 + 5 + 7/10
=235.7
looks like we have the number 235.7
decomposed into its different position values.
To solve the given problem, we need to simplify the expression by performing the calculations according to the rules of exponentiation and multiplication.
Let's break down the expression step by step:
1. 2 X 10^2 (2 multiplied by 10 squared):
Since 10 squared is 10 raised to the power of 2, we can calculate the exponent first:
10^2 = 10 x 10 = 100
Now, we multiply 2 by 100:
2 X 100 = 200
2. 3 X 10^1 (3 multiplied by 10 to the first power):
The exponent here is 1, which means we multiply 10 by itself once:
10^1 = 10
Now, we multiply 3 by 10:
3 X 10 = 30
3. 5 X 10^0 (5 multiplied by 10 to the power of 0):
Any number raised to the power of 0 is equal to 1. So, we have:
10^0 = 1
Now, we multiply 5 by 1:
5 X 1 = 5
4. 7 X 10^-1 (7 multiplied by 10 to the power of -1):
To calculate 10 raised to the power of -1, we need to take the reciprocal of 10, which is 1/10:
10^-1 = 1/10
Now, we multiply 7 by the fractional value:
7 X 1/10 = 7/10
Finally, we add up the results of each part:
200 + 30 + 5 + 7/10 = 235.7
So, the solution to the given problem is 235.7.