physics
posted by Anonymous .
A 417 kg pig is standing at the top of a muddy hill on a rainy day. The hill is 100m long with a vertical drop of 37.4 m. If the pig slips and begins to slide down the hill, assuming a negligible amount of friction what will be the pigs speed at the bottom of the hill?

Only the vertical drop H matters. The pig's mass and hill slope length don't matter.
g*H = V^2/2
where V is the velocity at the bottom.
Solve for V
V = sqrt(2 g H)