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A 417 kg pig is standing at the top of a muddy hill on a rainy day. The hill is 100m long with a vertical drop of 37.4 m. If the pig slips and begins to slide down the hill, assuming a negligible amount of friction what will be the pigs speed at the bottom of the hill?

  • physics -

    Only the vertical drop H matters. The pig's mass and hill slope length don't matter.

    g*H = V^2/2
    where V is the velocity at the bottom.

    Solve for V

    V = sqrt(2 g H)

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