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In the following reaction, how many grams of ferrous sulfide (FeS) will produce 0.56 grams of iron (III) oxide (Fe2O3)?
4FeS + 7O2 d 2Fe2O3 + 4SO2

  • chemistry -

    .56g of Fe2O3 = .56/159.69 = 0.0035 moles
    .0035 moles FeS = 0.307g FeS

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