Three objects are moving along a straight line as shown in the figure. Taking the positive direction to be to the right, what is the total momentum of this system?
Pos ---> 5.00 m/s, 8.00 kg
Neg <--- 4.00 m/s, 15.00 kg
Pos ---> 2.00 m/s, 3.00 kg
A) -14 kg m/s
B) +106 kg m/s
C) +14 kg m/s
D) -106 kg m/s
E) 0 kg m/s
total momentum = m1(v1)+m2(v2)+m3(v3)
total momentum = [(5)8]+[(-4)15]+[(2)3]
total momentum = (40)+(-60)+(6)
total momentum = (-20)+(6) = -14
Answer: A
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As shown in the diagram, three objects are moving along a straight line. Taking the positive direction to be to the right, what is the total momentum of this system?
A
To find the total momentum of the system, we need to calculate the momentum of each object and then sum them up.
Momentum is calculated using the formula: momentum = mass × velocity
The momentum of the first object (Pos) is calculated as:
momentum1 = mass1 × velocity1 = 8.00 kg × 5.00 m/s = 40.00 kg m/s (in the positive direction)
The momentum of the second object (Neg) is calculated as:
momentum2 = mass2 × velocity2 = 15.00 kg × (-4.00 m/s) = -60.00 kg m/s (in the negative direction)
The momentum of the third object (Pos) is calculated as:
momentum3 = mass3 × velocity3 = 3.00 kg × 2.00 m/s = 6.00 kg m/s (in the positive direction)
Now, we can add up the individual momenta:
Total momentum = momentum1 + momentum2 + momentum3
= 40.00 kg m/s + (-60.00 kg m/s) + 6.00 kg m/s
= -14.00 kg m/s
Therefore, the total momentum of the system is -14 kg m/s.
Hence, the correct option is A) -14 kg m/s.