# math

posted by .

solve equation 3(k-4.8)=0.7(k-6.9) show steps to solve this please

• math -

3(k-4.8)=0.7(k-6.9)

3*k-3*4.8=0.7*k-0.7*6.9

3k - 14.4 = 0.7k - 4.83

Subtracting 0.7k from each side:

3k -0.7k - 14.4 = 0.7k - 0.7k - 4.83

2.3k - 14.4 = -4.83

Adding 14.4 to each side

2.3k = 9.57

Dividing each side by 2.3:

k = 4.16

## Similar Questions

1. ### algebra

solve each literal equation for the indicated variable linear equation for x 2x+3y=6 can some one give me a example and show me how the steps go to solve this problem please Subtract 3y from both sides of the equation, and then divide …
2. ### Algebra

Solve the system of equations using substitution. x + 4y = -5 3x - 8y = 45 When I tried to solve it, I got x=-17 and y=-3. When I plugged these into the first equation, it didn't work out at all. Could someone please show me the steps …
3. ### Math

I need help with these three problems. They are on a Study Guide and I need some refreshing up of how to do them. 17. Solve the equation using the zero product property... -8n(5n+3) 19. Solve the equation by factoring 5z^2-2z-3=0 20. …
4. ### math

I need help with these three problems. They are on a Study Guide and I need some refreshing up of how to do them. 17. Solve the equation using the zero product property... -8n(5n+3) 19. Solve the equation by factoring 5z^2-2z-3=0 20. …
5. ### Math

I need help with these three problems. They are on a Study Guide and I need some refreshing up of how to do them. 17. Solve the equation using the zero product property... -8n(5n+3) 19. Solve the equation by factoring 5z^2-2z-3=0 20. …
6. ### algebra

solve the equation for x. 3x^2-2x-4=0. can you please show the steps?
7. ### Math

What steps do I take in order to solve : (101-100) = .512 times (x/.5) solve for x and show steps
8. ### Math

Solve for x: x^4-15X^2+14=0 How would I solve this problem?
9. ### math help please

solve the following quadratic equation and show steps 2z^4 +14z^3 + 20z^2
10. ### Math

solve the equation c/4 -5 =4 Please show all steps please!

More Similar Questions