What is the wavelength of waves transmitted by an AM radio station operating at a frequency of 840 kilohertz?

Calculate the energy of a photon whose frequency is 2450 megahertz

What is the difference in energy for a photon of ultra-violet radiation, wavelength 319 nm and a photon of ultra-violet radiation, wavelength 238 nm

The speed of light is c = 3*10^8 m/s

(1) wavelength = c/frequency
= 3*10^8/840*10^3 = ___ m
(2) E = h*frequency
h is Planck's cosntant. Look it up.
(3) E = h*c/(wavelength)
Calculate it for both wavelengths and take the difference.

thankss

I have a question how did you get 10^3?

To determine the wavelength of waves transmitted by an AM radio station operating at a frequency of 840 kilohertz, we can use the formula:

Wavelength (λ) = Speed of Light (c) / Frequency (f)

The speed of light is a constant value of approximately 3 x 10^8 meters per second, so we can substitute this value and the given frequency into the formula:

λ = 3 x 10^8 m/s / 840,000 Hz

Calculating this, we find:

λ ≈ 357.14 meters

Therefore, the wavelength of the waves transmitted by the AM radio station is approximately 357.14 meters.

Next, to calculate the energy of a photon with a frequency of 2450 megahertz, we can use the equation:

Energy (E) = Planck's constant (h) x Frequency (f)

Planck's constant is approximately 6.63 x 10^-34 joule-seconds (J·s), so we can substitute this value and the given frequency into the equation:

E = (6.63 x 10^-34 J·s) x (2,450 x 10^6 Hz)

Calculating this, we find:

E ≈ 1.62 x 10^-24 joules

Therefore, the energy of a photon with a frequency of 2450 megahertz is approximately 1.62 x 10^-24 joules.

Lastly, to find the difference in energy between two photons of ultraviolet radiation with wavelengths 319 nanometers (nm) and 238 nm, we can use the formula:

Energy (E) = Planck's constant (h) x Speed of Light (c) / Wavelength (λ)

Again, using the approximation for Planck's constant and the speed of light, we can substitute these values and the given wavelengths into the equation to calculate the energies:

For a wavelength of 319 nm:

E1 = (6.63 x 10^-34 J·s) x (3 x 10^8 m/s) / (319 x 10^-9 m)

Calculating this, we find:

E1 ≈ 6.57 x 10^-19 joules

And for a wavelength of 238 nm:

E2 = (6.63 x 10^-34 J·s) x (3 x 10^8 m/s) / (238 x 10^-9 m)

Calculating this, we find:

E2 ≈ 8.08 x 10^-19 joules

Therefore, the difference in energy between the two photons is approximately 8.08 x 10^-19 joules - 6.57 x 10^-19 joules = 1.51 x 10^-19 joules.