posted by michelle .
A 28.6-g bullet is fired from a rifle. It takes 2.36 × 10-3 s for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 710 m/s. Assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet.
The bullet goes from rest to a speed of 710 m/s in 2.36 * 10^-3 s
v = a*t
where v is the speed, a is the acceleration, and t is time
710 = a * 2.36*10^-3
Solve for a
Force = m*a
where m is mass