Show that one mole of KCLO3 contains 122.55 grams.
2 KCLO3(s)->2 KCL(s) + 3 O2(g)
K = 39.1 or thereabouts
Cl = 35.4 about
O = 3*16 = 48 about.
You can look up these numbers and add them.
Well, let's break it down. The molar mass of KCLO3 is approximately 122.55 grams per mole. Coincidence? I think not. It's almost as if someone planned it that way. So, when you have one mole of KCLO3, you get exactly 122.55 grams. It's like getting a perfect 10 in math, except it's chemistry. Just remember, chemistry is all about those balanced equations and the magical wonders they hold.
To calculate the molar mass of KCLO3, we need to consider the atomic masses of the elements involved:
K (potassium) = 39.10 g/mol
Cl (chlorine) = 35.45 g/mol
O (oxygen) = 16.00 g/mol
Now, let's calculate the molar mass of KCLO3:
Molar mass of KCLO3 = (K molar mass) + (Cl molar mass) + 3 x (O molar mass)
= (39.10 g/mol) + (35.45 g/mol) + 3 x (16.00 g/mol)
= 39.10 g/mol + 35.45 g/mol + 48.00 g/mol
= 122.55 g/mol
Therefore, one mole of KCLO3 contains 122.55 grams.
To show that one mole of KCLO3 contains 122.55 grams, we need to calculate the molar mass of KCLO3 and determine the number of moles in 122.55 grams of KCLO3.
1. Start by finding the molar mass of KCLO3. Use the periodic table to find the atomic masses of each element: K (potassium) = 39.10 g/mol, Cl (chlorine) = 35.45 g/mol, and O (oxygen) = 16.00 g/mol. KCLO3 consists of one potassium atom, one chlorine atom, and three oxygen atoms.
Molar mass of KCLO3 = (1 * 39.10 g/mol) + (1 * 35.45 g/mol) + (3 * 16.00 g/mol)
= 39.10 g/mol + 35.45 g/mol + 48.00 g/mol
= 122.55 g/mol
So, the molar mass of KCLO3 is 122.55 g/mol.
2. We know that one mole of any substance contains Avogadro's number (6.022 x 10^23) particles, whether they are atoms, molecules, or ions. In this case, we are dealing with a compound (KCLO3).
3. Now, we can use the molar mass to determine the number of moles in 122.55 grams of KCLO3. We use the formula:
Number of moles = Mass of substance / Molar mass
Plugging in the values:
Number of moles = 122.55 g / 122.55 g/mol
= 1 mole
Hence, 122.55 grams of KCLO3 is equal to one mole.