In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.
a. Find the percent of increase in the newspaper’s circulation from 2000 to 2001 and from 2001 to 2002.
b. Which period had a higher percent of increase, 2000 to 2001, or 2001 to 2002? (3 points)
Is my answer correct?
2000 - 2001: 3640 - 3250 = 390
2001 - 2002: 4100 - 3640 = 460
2001 to 2002 had the higher percent of increase.
The percent change is (new-original)/original.
(3640 - 3250) / 3250 = 390 / 3250 = 39 / 325 = 3 / 25 = 12%
(4100 - 3640) / 3640 = 460 / 3640 = 46 / 364 = 23 / 182 = 12.637...%
The largest change came from 2001 to 2002.
#2018
I thought it was 460 not 450......?
To find the percent of increase, you need to calculate the difference in circulation between the two years and then divide it by the initial circulation. Afterward, multiply the result by 100 to get the percentage.
Let's calculate the percent of increase from 2000 to 2001:
Circulation in 2000: 3,250
Circulation in 2001: 3,640
The difference in circulation is: 3,640 - 3,250 = 390.
The percent of increase is: (390 / 3,250) * 100 ≈ 12%.
Now, let's calculate the percent of increase from 2001 to 2002:
Circulation in 2001: 3,640
Circulation in 2002: 4,100
The difference in circulation is: 4,100 - 3,640 = 460.
The percent of increase is: (460 / 3,640) * 100 ≈ 12.6%.
Therefore, your calculation is incorrect. The correct values are:
From 2000 to 2001: approximately 12% increase.
From 2001 to 2002: approximately 12.6% increase.
As for the second part of your question, you are right. The percent of increase from 2001 to 2002 is higher than that from 2000 to 2001. So, the period from 2001 to 2002 had a higher percent of increase in the newspaper's circulation.
It is difference divided by start
So now you need to take the 390 and divide by 3250
And take the 450 and divide by 3640
390 and 450 are the amount of increase not the percent of increase