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Lee Holmes deposited \$ 15,000 in a new savings account at 9% interest compounded semiannually, At the beginning of year 4, Lee deposites an additional \$40000 at 9% interest compounded semiannually. At the end of the 6 years what is the balance in Lee;s account

P1 = Po(1+r)^n.

P1 = Principal after 1st 3 years.

Po1 = \$15,000 = Initial deposit @ beginning of the 1st 3 years.

r = (9%/2)/100% = 0.045 = Semi-annual %
rate expressed as a decimal.

n = 2Comp/yr * 3yrs = 6 Compounding
periods.

Solve the given Eq and get:
P1 = \$19,533.90.

P2 = Po2(1+r)^n.

P2 = Principal amount after the 2nd 3 years.

Po2 = 19,533.90 + \$40,000 = \$59,533.90
= Initial deposit for 2nd 3 years.

Solve for P2.

NOTE: r,and n are the same for both P1 and P2 calculations.

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