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A high diver of mass 68.2 kg jumps off a board 10.4 m above the water.
The acceleration of gravity is 9.8 m/s2 .
If his downward motion is stopped 3.58 s after he enters the water, what average upward force did the water exert on him?
I already calculated that his velocity before hitting the water is 14.277 m/s.

  • Physics -

    v₀=sqrt(2gh)=sqrt(2•9.8•10.4)=14.28 m/s
    v= v₀-at, v=0 =>
    a= v₀/t = 14.28/3.58 =4 m/s²
    F=ma=68.2•4=272.8 N

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