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what is the pH of the solution formed when 25 mL of 0.173 M NaOH is added to 35 mL of 0.342 M HCl?

  • chemistry -

    millimols HCl = 35 mL x 0.342M = ?
    mmols NaOH = 5 x 0.173 = ?
    Calculate each, determine the one in excess, calculate the amount in excess, then if acid pH = -log(H^+) or if basic then pOH = -log(OH^-) and convert to pH by pH + pOH = pKw = 14.

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